Multiplicity of peak in 1H-NMR spectrum is splitting of one peak in to two or many peaks.
Hi Friends, in this article we will learn about splitting and multiplicity of peak in 1H-NMR. In previous article we have seen that how we can find coupling constant or J-value of the peak in 1H-NMR spectrum.[Link]
We have discussed various applications of spectroscopy in chemistry, medicine and environmental science in another article. Please check out for more details. [Link]
Let’s understand both the
terminologies;
Introduction
What is splitting of peak?
If a peak appears as single line,
then it is known as “singlet”. There are certain situations where singlet peak
divided into two or many lines, this phenomenon is known as splitting of the
peak.
What is multiplicity of peak?
The number of lines formed due to
splitting is known as multiplicity.
Some of the splitting patterns
are given below;
Table :1 Splitting and multiplicity in Proton NMR |
How to calculate multiplicity of
the peak?
We can predict multiplicity of
peak which is formed by splitting of that peak by using following formula;
Multiplicity
of peak = No. of H on adjacent Carbon + 1
Let’s
understand this with some examples
Ethyl acetate
Ethyl
acetate is an ester compound which has formula as shown below.
It has
three types of proton groups;
CH3 (red
colour)
CH3 (blue
colour)
And CH2
So the 1H-NMR spectrum shows
three different peaks.
Now we will see multiplicity for
each peak.
CH3 (red colour) does not have H
on adjacent carbon, so according to formula;
Multiplicity
of peak = No. of H on adjacent Carbon + 1
Multiplicity
of peak = 0 + 1
Multiplicity
of peak = 1 (one line)
That mean
peak for CH3 (red) appears as “singlet”.
In
similar way multiplicity of CH3 (blue) can be calculated. It has adjacent CH2.
Therefore,
Multiplicity
of peak = No. of H on adjacent Carbon + 1
Multiplicity
of peak = 2 + 1
Multiplicity
of peak = 3 (three lines)
That mean
peak for CH3 (blue) appears as “triplet”.
what
about CH2 peak?
CH2 group
has adjacent CH3
Hence according
to above formula;
Multiplicity
of peak = No. of H on adjacent Carbon + 1
Multiplicity
of peak = 3 + 1
Multiplicity
of peak = 4 (four lines)
Therefore,
we can predict that CH2 peak appears as “Quartet”.
Let’s see
another example;
Propane
Propane
molecule consist of two types of protons, that is two CH3 and one CH2.
What will
be multiplicity of CH3 peak? It has 3 H on adjacent carbon.
So, according
to formula,
Multiplicity
of peak = No. of H on adjacent Carbon + 1
Multiplicity
of peak = 2 + 1
Multiplicity
of peak = 3 (three lines)
So, it is
clear that CH3 peak appears as “triplet”
Now we
will see multiplicity of CH2 peak, here it has 6 H on adjacent carbon.
Therefore,
Multiplicity
of peak = No. of H on adjacent Carbon + 1
Multiplicity
of peak = 6 + 1
Multiplicity
of peak = 7 (seven lines)
This type
of multiplicity is known as “septet”.
1-bromobutane
1-bromobutane
molecule has four types of protons groups.
That
means 1H-NMR shows four different peaks.
Possible multiplicity of each peak is described in table,
Table 2: Multiplicity of protons in 1-bromobutane |
Friends, I
hope that from above examples we learned how to find multiplicity of the peak
in 1H-NMR.
We can
also find out distance between two lines of the peak. It is known as coupling
constant or J value. This we have discussed in previous article. I would
suggest that after understanding multiplicity, please check coupling constant
calculations.
If you
feel this information helpful, then please do write in the comment section
below.
That’s all for this topic. See you in the next blog.
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