Definitions
In a chemical reaction amount of product formed is known as yield of that reaction. Theoretically we can calculate the amount of product formed as the reaction completes. The ideal amount of product formed in the reaction is known as theoretical yield. But in practical theoretical yield cannot be isolated because of various factors such reaction conditions, chromatographic purifications and formation of by products. Hence the isolated yield is always compared with theoretical yield and it is reported in percentage also known as percent yield.
For
example consider a hypothetical reaction in which compound A (1 mol) and
compound B (1 mol) reacts together to form compound AB. If there is no by product
form in the reaction then theoretically 1 mol of compound AB should form as a
result of reaction. Now consider that compound A has molecular weight 100 g/
mol and compound B has molecular weight 50 g/mol. Therefore molecular weight of
compound will be 150 g/mol. In the reaction if we used 1 g of compound A (1/100
= 0.01 moles) then compound B is needed 0.01 moles. To calculate required
amount of compound B we need multiply 0.01 moles x molecular weight; therefore
0.01 moles x 50 = 0.5 g. The compound AB formed in the reaction should be 0.01
moles. (Table 1)
Reaction |
|||
Compound |
A |
B |
AB |
Molecular
Wt. |
100 g /mol |
50 g/mol |
150 g/mol |
Amount |
1g |
0.01 x 50 = 0.5 g |
------ |
Moles
|
1g / 100 g = 0.01 moles |
0.01 moles |
0.01 moles |
Calculation of theoretical yield
Case 1
Suppose
in this reaction a limiting reagent is compound A. So the theoretical yield is
calculated by the formula;
If
compound B is limiting agent in this reaction then theoretical yield is calculated
by the formula;
Hence
from the reaction of compound A and B the maximum amount of compound AB will be
1.5 g.
The
actual yield of reaction may or may not be equal to the theoretical yield. Loss
of yield is due to methods of purification of the compounds. Hence actual yield
or isolated yield is always compared with theoretical yield and written in
percentage. Suppose in above reaction actual yield is 1.1 g. So the percent
yield can be calculated by the formula;
Hence
percent yield of the reaction is 73.33 %.
Consider
the reaction of methyl benzoate with lithium borohydride to produce benzyl
alcohol. In this reaction for 1 mole of ester compound there is requirement of
2 moles of lithium borohydride. Calculation for the reaction is shown in table
2.
Reaction |
|||
Compound |
methyl benzoate |
LiAlH4 |
benzyl alcohol |
Molecular Wt. |
136.15 g /mol |
37.95 g/mol |
108.14 g/mol |
Amount |
1g |
(0.0073 x 2) x 37.95 = 0.554 g |
------ |
Moles |
1g / 136.15 g = 0.0073 moles |
0.0073 x 2 |
0.0073 moles |
Calculation of Theoretical Yield
Here
methyl benzoate is limiting regent because it is used in least quantity.
Therefore theoretical yield is calculated by the formula;
Calculation of Percent Yield
Suppose
actual yield of the reaction after purification of the compound is 0.5 g; then
percent yield is calculated as below;
Hence
percent yield of the reaction is 62.97 %.
How to calculate overall yield
of multi-step synthesis?
In
organic chemistry many compounds are synthesized by linear synthesis that is
the molecules required series of reactions. Each step in the synthesis has
different yield of reaction. Therefore it is necessary to understand amount of final
compound as a result of all the steps. This gives exact idea of productivity of
the multi-step synthesis.
For
example; consider a hypothetical multistep synthesis which has three steps. In
this reaction scheme step 1 gives 70 % yield, step 2 has 80 % yield and step 3
gives the final product in 90 % yield. Therefore overall yield of the reaction
scheme is calculated by the formula;
Hence
overall yield of multi-step synthesis is 50.4 %.
Consider
another multi-step synthesis which has five steps involved in it. Yield of each
step is shown below;
Overall
yield of the synthetic scheme is calculated by the formula;
Hence
overall yield of multistep synthesis is 17.27 %.
Overall
yield calculation of the synthetic route can gives idea about how efficient the
route is.
For example, consider the four step linear synthesis of compound E, starting from compound A. Let’s consider that each step gives 50 % yield.
Therefore overall yield of the multi-step synthesis is calculated by the formula;
Hence
it is understood that overall yield of the synthetic route is 6.25 %
Now consider another route which is convergent synthesis of compound E.
Overall
yield of the synthetic route is calculated by the formula;
Here
the overall yield of the convergent synthesis is 12.5 %. It is better than
linear synthesis of compound E.
From
above calculation of overall yield of synthetic route we can choose the
efficient route for the synthesis of organic compounds.
That's all for this topic. If you have any questions please feel free to ask me in the comment box. Thank you..!
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