Introduction
Organic
compounds are consisting of carbon (C), hydrogen (H) and oxygen (O). Along with
these three main elements found in organic molecules there are certain amount
of nitrogen (N) and halogens (F, Cl, Br, I) found in organic compounds. As we studied that molecular
formula of the compound only gives idea about constituents of the molecule and
molecular weight. It does not give any information of structure of the
molecule. For the structure analysis there are various methods available like
Mass spectrometry, UV, IR and NMR spectroscopy. In the analysis process from
molecular formula if we able to know the number of rings, double and triple
bonds then it will be very useful for the identification of compounds by above
methods. Also we can find out various isomers of compounds which are having
same molecular formula.
In
this context degree of unsaturation of compound is calculated. It is also known
as index of hydrogen deficiency (IHD) or unsaturation index. Each degree of
unsaturation is equal to 1 pi
bond
or ring.
A
simplified formula for the degree of unsaturation is;
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Figure: 1 Degree of Unsaturation
Example 1
Let’s
see the molecular formula C5H8NClO, now calculate degree
of unsaturation by using above formula;
Example 2
Chemical
Formula: C6H5Br2NO
Example 3
Degree
of unsaturation helps to find out various structures of given formula.
Suppose
an unknown organic compound has molecular formula C4H8, what
could be the possible structure?
According
to the formula; the unknown compound has 4 carbon atoms and 8 hydrogen atoms.
Therefore degree of unsaturation is calculated as;
The degree of unsaturation 1 suggests that there is one double bond or ring. Therefore possible structures are A or B or C.
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Figure 2: Isomers of the chemical formula C4H8 |
The
compound A, B or C all have same molecular formula but the structures are
different. So the spectral features like IR and NMR spectra are different. Calculation
of degree of unsaturation helps in identification of possible structures of
organic compounds. This is needed to determination of various isomers of the
compounds.
Example 4
Consider the molecular formula C6H6, now let’s calculate degree of unsaturation for the formula.
Since
degree of unsaturation is 4, that means there are three possibilities
a) 1) 4
pi bonds
b) 2) 3
pi bonds + 1 ring
c) 3) 2
pi bonds + 2 rings
T Possible structures of the chemical formula C6H6 are given in Table 1
That's all for this topic. If you have any questions please feel free to ask me in the comment box. Thank you..!
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